Can anyone show me how to solve these two equations sin2x=-sinx between 0 and 360 degrees also sinxtanx-sinx=0 I am not sure how do these.
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Originally Posted by homeylova223 Can anyone show me how to solve these two equations sin2x=-sinx between 0 and 360 degrees Note that sin(2x) = 2 sin(x) cos(x), so 2 sin(x) cos(x) = -sin(x) 2 sin(x) cos(x) + sin(x) = 0 sin(x) [2 cos(x) + 1] = 0 Can you take it from there? -Dan
Originally Posted by homeylova223 sinxtanx-sinx=0 sin(x) tan(x) - sin(x) = 0 sin(x) [ tan(x) - 1 ] = 0 etc. -Dan
You are really skilled in math.
Originally Posted by homeylova223 You are really skilled in math. No really. I'm blushing... -Dan
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