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Math Help - Trigonometry math help.. confirmation?

  1. #1
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    Trigonometry math help.. confirmation?

    i been trying to solve this but can't seem to get the wrong answer, can anyone help me located where i went wrong?

    3cot^2(x)=1 , x is greater than or equal to 0 and less than 2pi

    cot(x) = 1/square root 3

    x = 60 degree or pi / 3

    shouldn't the 4 answers be pi/3, -2pi/3, 4pi/3, and -5pi/3
    correct me if im wrong please. thank you!
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by ASUSpro View Post
    i been trying to solve this but can't seem to get the wrong answer, can anyone help me located where i went wrong?

    3cot^2(x)=1 , x is greater than or equal to 0 and less than 2pi

    cot(x) = 1/square root 3

    x = 60 degree or pi / 3

    shouldn't the 4 answers be pi/3, -2pi/3, 4pi/3, and -5pi/3
    correct me if im wrong please. thank you!
    Two of these are correct. Note that your solution set needs to be 0 \leq \theta < 2 \pi. What does this do to your negative solutions?

    -Dan
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    I can't add 360 degree , that wil make them out of range, do i just remove the negative signs?
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    Forum Admin topsquark's Avatar
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    Quote Originally Posted by ASUSpro View Post
    I can't add 360 degree , that wil make them out of range, do i just remove the negative signs?
    The solution -2 \pi /3 is in QIII, so we have a reference angle of \pi /3 below the -x axis. Thus the angle -2 \pi /3 is the same as \pi + \pi / 3 = 4 \pi / 3 which is already on your list.

    -Dan
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