Thread: Trigonometry math help.. confirmation?

i been trying to solve this but can't seem to get the wrong answer, can anyone help me located where i went wrong?

3cot^2(x)=1 , x is greater than or equal to 0 and less than 2pi

cot(x) = 1/square root 3

x = 60 degree or pi / 3

shouldn't the 4 answers be pi/3, -2pi/3, 4pi/3, and -5pi/3
correct me if im wrong please. thank you!

Originally Posted by ASUSpro

i been trying to solve this but can't seem to get the wrong answer, can anyone help me located where i went wrong?

3cot^2(x)=1 , x is greater than or equal to 0 and less than 2pi

cot(x) = 1/square root 3

x = 60 degree or pi / 3

shouldn't the 4 answers be pi/3, -2pi/3, 4pi/3, and -5pi/3
correct me if im wrong please. thank you!

Two of these are correct. Note that your solution set needs to be . What does this do to your negative solutions?

-Dan

I can't add 360 degree , that wil make them out of range, do i just remove the negative signs?

Originally Posted by ASUSpro

I can't add 360 degree , that wil make them out of range, do i just remove the negative signs?

The solution is in QIII, so we have a reference angle of below the -x axis. Thus the angle is the same as which is already on your list.

-Dan