Can anyone help me solve these two problems sin2x-1=0 2sinx cox-1=0 Then I am not sure how to proceed sinxtanx-sinx=0 sinx (sinx/cosx)- sinx Sinx^2/ cosx -sinxcosx/cosx I am not sure if I am doing this right?
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It's easier not to expand. Add 1 to both sides: Take the arcsin of both sides:
Thanks for your help however the second function I am still having problem solving. I narrowed it down to sinx^2-sinx=0 factor sin sinx(sinx-1)=0 sinx=0 sinx=1 x=0, 90,180,270,360 degrees?
Last edited by homeylova223; Mar 1st 2011 at 06:21 PM.
Originally Posted by homeylova223 How would you take the arcsin in the equation I am not sure how to do it? Arcsine (or asn or ) is the inverse of the sine function. So if we know that y = sin(x) then . (The angle x is written in the form ) Thus and because . -Dan
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