Can anyone help me solve these two problems
2sinx cox-1=0 Then I am not sure how to proceed
sinx (sinx/cosx)- sinx
Sinx^2/ cosx -sinxcosx/cosx I am not sure if I am doing this right?
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It's easier not to expand.
Add 1 to both sides:
Take the arcsin of both sides:
Thanks for your help however the second function I am still having problem solving.
I narrowed it down to
sinx^2-sinx=0 factor sin
x=0, 90,180,270,360 degrees?
Last edited by homeylova223; March 1st 2011 at 06:21 PM.
Originally Posted by homeylova223 How would you take the arcsin in the equation I am not sure how to do it? Arcsine (or asn or ) is the inverse of the sine function. So if we know that y = sin(x) then . (The angle x is written in the form )
and because .
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