Hi there,

My question is:

Solve Equation

4sin(x)^2 + 7sin(x) = 2

Here is what I did:

4sin(x)^2 + 7sin(x) -2 = 0

(4sinx - 1)(1sinx + 2) = 0

4sinx -1 = 0 or Sinx +2 =0

sinx = (1/4) Sinx = -2

I multiplied both sides of each equation by the inverse of sin resulting in:

Sinx = (1/4) at 0.25 radians - (14.48 degrees) in quadrant one, and 104.47 degrees in quadrant two (90 degrees + 14.48 = 104.48 degrees)

Sinx = -2 is not possible - no solution.

My professor has never used obscure degrees like this before, so I'm wondering if I'm doing something wrong. Any suggestions?

Thanks in advance!

PurplePonies