Im stuck on this question in my maths homework:
Solve the equation √3tan2x-1=0 for 0<X<π
Here is what i've done:
Using trig identities,
so tan2x=sin2x/cos2x < is this right?
I've then used the trig expansions:
2sinxcosx/1-2sin^2x < Am I using the right expansion for cos2x?
Am I using the right method? I have tried to go further than this, but nothing has worked out, so where do I go from here?
Thanks in advance.