In a right triangle given a=32.8ft and A= 28 deg 30’15” , solve for b and c
$\displaystyle \left(28+\frac{30}{60}+\frac{15}{360} \right)^\circ =\frac{685 }{24}^\circ$
Using the Sine Rule:
$\displaystyle \frac{a}{\sin A}=\frac{b}{\sin B} = \frac{c}{\sin C}$
$\displaystyle \frac{32.8}{\sin(\frac{685}{24})}=\frac{c}{\sin90}$
$\displaystyle c \approx 68.65$
Use pythag to get b:
$\displaystyle b=\sqrt{68.65^2+32.8^2}\approx 76.08$
Then use the sine rule again to solve for angle B.