Prove: $\displaystyle sin^{2}(\alpha -\beta ) = sin^{2}\alpha - sin^{2}\beta +2sin\alpha .sin\beta .cos(\alpha- \beta )$
Last edited by mr fantastic; Feb 26th 2011 at 01:01 PM. Reason: Re-titled.
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Originally Posted by arm Prove: $\displaystyle sin^{2}(\alpha -\beta ) = sin^{2}\alpha - sin^{2}\beta +2sin\alpha .sin\beta .cos(\alpha- \beta )$ To get help you need to show some effort. Show your work and say where you're stuck.
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