Proving expression with sines.

Printable View

February 26th 2011, 10:16 AM
arm

Proving expression with sines.

Prove: $sin^{2}(\alpha -\beta ) = sin^{2}\alpha - sin^{2}\beta +2sin\alpha .sin\beta .cos(\alpha- \beta )$
February 26th 2011, 01:00 PM
mr fantastic

Quote:

Originally Posted by arm

Prove: $sin^{2}(\alpha -\beta ) = sin^{2}\alpha - sin^{2}\beta +2sin\alpha .sin\beta .cos(\alpha- \beta )$

To get help you need to show some effort. Show your work and say where you're stuck.

All times are GMT -8. The time now is 08:08 PM.

Copyright © 2005-2013 Math Help Forum. All rights reserved.

Copyright © 2005-2013 Math Help Forum. All rights reserved.