If a ↓ b than a ↓ b = (a*b/(|b|^2))b and b ↓ a = (b*a/(|a|^2))a correct? If not, why will b ↓ a will still be (b*a/(|a|^2)) but with a multiple of b at the end? That is why my book is saying in the back. That it is still vector b as compared to vector a.
my question is if it is always b? An example is below:
Vectors a and b are such that |a| = 5, |b| = 3, and the angle between them is 150^o. Determine a ↓ b and b ↓ a.
The book claims it is (-(5*(3)^0.5)/6)*b and (-3(3)^0.5/10)b. Why is it two b and not b and then a?