1. ## trig equation

Solve the equation 4 + 3 sin (2x – 1) = 6 for 0 < x < pi/2. please help me solve this equation

2. $\displaystyle 4 + 3\sin{(2x-1)} = 6$

$\displaystyle 3\sin{(2x-1)} = 2$

$\displaystyle \sin{(2x-1)} = \frac{2}{3}$

$\displaystyle 2x-1 = \arcsin{\left(\frac{2}{3}\right)}$

$\displaystyle 2x = 1 + \arcsin{\left(\frac{2}{3}\right)}$

$\displaystyle x = \frac{1}{2} + \frac{1}{2}\arcsin{\left(\frac{2}{3}\right)}$

3. Originally Posted by loraltmath
Solve the equation 4 + 3 sin (2x – 1) = 6 for 0 < x < pi/2. please help me solve this equation
sin(2x-1)=2/3

2x-1=arcsin(2/3)

solve for x make sure calc is in radians

4. make sure calc is in radians
thank you, but how do i do this?

5. Originally Posted by loraltmath
thank you, but how do i do this?
Are you saying that you do not know what "radians" are? Do you understand what the condition you stated, " $0\le x\le \pi/2$" means?

If you are using a calculator to find arcsin(2/3), do you know how to set the "mode" of your calculator? For example, the calculator that comes with Windows has buttons that give "Degrees", "Radians", and "Grad".