Solve the equation 4 + 3 sin (2x – 1) = 6 for 0<x<pi/2. please help me solve this equation

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- Feb 22nd 2011, 06:15 AMloraltmathtrig equation
Solve the equation 4 + 3 sin (2x – 1) = 6 for 0

__<__x__<__pi/2. please help me solve this equation - Feb 22nd 2011, 06:26 AMProve It
$\displaystyle \displaystyle 4 + 3\sin{(2x-1)} = 6$

$\displaystyle \displaystyle 3\sin{(2x-1)} = 2$

$\displaystyle \displaystyle \sin{(2x-1)} = \frac{2}{3}$

$\displaystyle \displaystyle 2x-1 = \arcsin{\left(\frac{2}{3}\right)}$

$\displaystyle \displaystyle 2x = 1 + \arcsin{\left(\frac{2}{3}\right)}$

$\displaystyle \displaystyle x = \frac{1}{2} + \frac{1}{2}\arcsin{\left(\frac{2}{3}\right)}$ - Feb 22nd 2011, 06:27 AMPlague01
- Feb 22nd 2011, 07:06 AMloraltmathQuote:

make sure calc is in radians

- Feb 23rd 2011, 03:30 AMHallsofIvy
Are you saying that you do not know what "radians" are? Do you understand what the condition you stated, "$\displaystyle 0\le x\le \pi/2$" means?

If you are using a calculator to find arcsin(2/3), do you know how to set the "mode" of your calculator? For example, the calculator that comes with Windows has buttons that give "Degrees", "Radians", and "Grad".