can someone solve the triange im really stuck on it
So $\displaystyle \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} $.
$\displaystyle \frac{50}{\sin 81.65} = \frac{b}{\sin 60} $. Solve for $\displaystyle b $. Then you can solve for the height from this information. So $\displaystyle \frac{h}{\sin 42.6} = \frac{b}{\sin 47.4} $. We already know $\displaystyle b $. So solve for $\displaystyle h $. So $\displaystyle h = \frac{b \sin 42.6}{\sin 47.4} $ or $\displaystyle h \approx 3.60b = 1748.661 $.