I know I am missing something simple. $\displaystyle tan\theta=\frac{-1}{2}$ Having a hard time figuring out what $\displaystyle \theta$ is.

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- Jul 25th 2007, 05:28 PMPossible actuaryHelp with simple tangent problem
I know I am missing something simple. $\displaystyle tan\theta=\frac{-1}{2}$ Having a hard time figuring out what $\displaystyle \theta$ is.

- Jul 25th 2007, 06:00 PMtukeywilliams
Look at a 30-60-90 right triangle. Alternatively use the definition $\displaystyle \tan \theta = \frac{\sin \theta}{\cos \theta} $.

- Jul 26th 2007, 04:35 AMtopsquark