# Help with simple tangent problem

• Jul 25th 2007, 05:28 PM
Possible actuary
Help with simple tangent problem
I know I am missing something simple. $tan\theta=\frac{-1}{2}$ Having a hard time figuring out what $\theta$ is.
• Jul 25th 2007, 06:00 PM
tukeywilliams
Look at a 30-60-90 right triangle. Alternatively use the definition $\tan \theta = \frac{\sin \theta}{\cos \theta}$.
• Jul 26th 2007, 04:35 AM
topsquark
Quote:

Originally Posted by Possible actuary
I know I am missing something simple. $tan\theta=\frac{-1}{2}$ Having a hard time figuring out what $\theta$ is.

This one doesn't come out nice, so you're stuck with using technology. From my calculator I get that $\theta = tan^{-1} \left ( - \frac{1}{2} \right ) \approx -26.5651^o$.

-Dan