Trigonometric Ratios

**vaironxxrd** · February 17th 2011, 05:51 PM

Hello Guys here its a Geometry homework i had, and i just want to check with you guys if i did this question right since is kind of confusing. First my answers and then the picture with the question just making sure i got the right answer here... I could not scan the steps.
---Rounded to the nearest thousand---
D=5168FT

X=1768FT

(Image)

Uploaded with ImageShack.us

**Ackbeet** · February 17th 2011, 05:54 PM

Can you find the vertical drop?

**vaironxxrd** · February 17th 2011, 05:57 PM

Originally Posted by Ackbeet

Can you find the vertical drop?

They are listed above .

"D=5168FT

X=1768FT"

BTW the book did not list these i found the vertical drop by first solving D which is the distance a person would travel at the slope.. Sorry for the lots of TYPOS

**Ackbeet** · February 17th 2011, 06:01 PM

Hmm. Well, the vertical drop figure, at least, can't possibly be right. How did you get that answer?

**vaironxxrd** · February 17th 2011, 06:28 PM

Originally Posted by Ackbeet

Hmm. Well, the vertical drop figure, at least, can't possibly be right. How did you get that answer?

Took the Focus angle which was 20(Degrees),found out it was opposite over hypotenuse which is Sin
So SIN(20)= $\dfrac{x}{5168}$

**skeeter** · February 17th 2011, 06:42 PM

where did the number 5169 come from ?

from the picture, $x = 5500 - 5018 = 482 \, ft$

$\sin(20^\circ) = \dfrac{x}{d}$

solve for $d$

**Prove It** · February 17th 2011, 06:45 PM

You're going about this wrong. The value of $\displaystyle X$ is KNOWN - it's $\displaystyle 5500 - 5018 = \dots$ .

You use THIS value to find $\displaystyle D$ .

**vaironxxrd** · February 18th 2011, 02:20 AM

Originally Posted by skeeter

where did the number 5169 come from ?

from the picture, $x = 5500 - 5018 = 482 \, ft$

$\sin(20^\circ) = \dfrac{x}{d}$

solve for $d$

Originally Posted by Prove It

You're going about this wrong. The value of $\displaystyle X$ is KNOWN - it's $\displaystyle 5500 - 5018 = \dots$ .

You use THIS value to find $\displaystyle D$ .

I will solve it from school. But why are we doing elevation-elevation or (5500)-(5018)

**Prove It** · February 18th 2011, 02:33 AM

You start off 5018 ft above the ground and end up 5500 ft above the ground. How far have you travelled vertically?

**Archie Meade** · February 18th 2011, 04:39 AM

Originally Posted by vaironxxrd

Hello Guys here its a Geometry homework i had, and i just want to check with you guys if i did this question right since is kind of confusing. First my answers and then the picture with the question just making sure i got the right answer here... I could not scan the steps.
---Rounded to the nearest thousand---
D=5168FT

X=1768FT

(Image)

Uploaded with ImageShack.us

You appear to have added 150 ft onto 5018 ft to get D.
Why ?

In your sketch, it states

The vertical drop is the difference in the elevations

**vaironxxrd** · February 18th 2011, 05:35 AM

Originally Posted by Archie Meade

You appear to have added 150 ft onto 5018 ft to get D.
Why ?

In your sketch, it states

The vertical drop is the difference in the elevations

I actually Took the Focus angle which is 20(Degrees) and found out it was COS Because Adjacent over hypotenus. GOT [Math]\dfrac{COS20}{1}=[/tex] $\dfrac{5500}{D}$

**Archie Meade** · February 18th 2011, 05:51 AM

Originally Posted by vaironxxrd

I actually Took the Focus angle which is 20(Degrees) and found out it was COS Because Adjacent over hypotenus. GOT [Math]\dfrac{COS20}{1}=[/tex] $\dfrac{5500}{D}$

Ok,

You are incorrectly taking that elevation as being the length of the top horizontal blue line,
(whose purpose mainly is to illustrate the angle of depression),
whereas the elevation is "height above sea-level".

(And if that was it's length, D would be longer)

**vaironxxrd** · February 18th 2011, 06:12 AM

Originally Posted by Archie Meade

Ok,

You are incorrectly taking that elevation as being the length of the top horizontal blue line,
(whose purpose mainly is to illustrate the angle of depression),
whereas the elevation is "height above sea-level".

(And if that was it's length, D would be longer)

I already fixed it but still I get 1409 ft for D
For X I got 482ft

**Archie Meade** · February 18th 2011, 06:32 AM

Originally Posted by vaironxxrd

I already fixed it but still I get 1409 ft
For X I got 482ft

That seems fine for D

**vaironxxrd** · February 18th 2011, 08:53 AM

Originally Posted by Archie Meade

That seems fine for D

yea sorry i did not express it .. I was rushing through the steps i think that is why i get them wrong i usually rush

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