Solving another simple trig. equation...

The equation is...

$\displaystyle 1+cot^2\Theta-3csc\Theta=0$

I tried substituting $\displaystyle \dfrac{cos^2\Theta}{sin^2\Theta}$ for $\displaystyle cot^2\Theta$ and replaced $\displaystyle csc\Theta$ with $\displaystyle \dfrac{1}{sin\Theta}$.

I was left with...

$\displaystyle \dfrac{cos^2\Theta}{sin^2\Theta}-\dfrac{3}{sin\Theta}=-1$

And now i'm pretty confused. I tried cross multiplying and getting a common denominator, but that just kept me going in circles. Which is when i realized i was doing something wrong.