Hello
How would I go about converting 9 sin120 into the form with a surd:
9*(squareroot of 3)
-------------------
............2
?
Thank you :)
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Hello
How would I go about converting 9 sin120 into the form with a surd:
9*(squareroot of 3)
-------------------
............2
?
Thank you :)
You should know thatfor
.
value from the unit circle ...Quote:
Originally Posted by anees7112
http://math.asu.edu/~arce/Unit%20Cir...nit_circle.gif
Although the other two methods are easier you can use the fact that = \sin A \cos B + \cos A \sin B \text{ where } A = 90^{\circ} \text{ and } B = 30^{\circ})
30 and 90 are, of course, found on a 30-60-90 triangle