Hey, I have been working a bit with the trig functions and came across this problem:
B = (A + sin(theta) )/ (sin(theta)*cos(theta))
when you separate the above fraction into the following:
C = A/(sin(theta)*cos(theta))
D = sin(theta) / (sin(theta)*cos(theta)) => 1/ cos(theta)
C+D != B if theta = 0 as sin(0) = 0 and cos(0) = 1
I came across this problem when trying to solve :
a - b*cos(theta) - b^2*sin(theta) = 0
Is there any method to make sure that this doesnt happen or do you just have to check the formula through for this?
Thanks for any replies.
<-- Square both sides
Now, , so
Now let . Then your equation is
which is a quadratic you can solve for y.
Note: When doing this you MUST check your solutions for in the original equation for as the method I am using here is likely to add spurious solutions.