Thread: Confusion of finding asymtotes from trig function

I am having a hard time on comprehending where the asymptotes lie on a variety of trig questions.

y= sec(x/2) > [0,2pie]
-the help sheet clearly states that when plotting a sec graph, the asymptotes are located in the domain of [0,2pie] at pie/2 and 3pie/2, but the answer repels this and has the asymptotes at just pie. What am i doing wrong?

y= cot(3x) > [0,2pie]
-the help sheet clear states that the asymptotes are located in the domain of [0,2pie] at 0,pie and 2 pie, yet the answer locates the asymptotes at pie/3, 2pie/3, pie, 4pie/3, 5pie/3 and 2pie........why are there more than the normal amount? is it because there is a number in the brackets, making there more cycles therefor more asymptotes, i am unsure. It would be very helpful if someone could provide me with a bit of detail on this.

Originally Posted by johnsy123

I am having a hard time on comprehending where the asymptotes lie on a variety of trig questions.

y= sec(x/2) > [0,2pie]
-the help sheet clearly states that when plotting a sec graph, the asymptotes are located in the domain of [0,2pie] at pie/2 and 3pie/2, but the answer repels this and has the asymptotes at just pie. What am i doing wrong?

y= cot(3x) > [0,2pie]
-the help sheet clear states that the asymptotes are located in the domain of [0,2pie] at 0,pie and 2 pie, yet the answer locates the asymptotes at pie/3, 2pie/3, pie, 4pie/3, 5pie/3 and 2pie........why are there more than the normal amount? is it because there is a number in the brackets, making there more cycles therefor more asymptotes, i am unsure. It would be very helpful if someone could provide me with a bit of detail on this.

Note that



Whenever cosine is 0, the sec graph will have an asymptote, and the same applies to tangent.

The question you should ask yourself is where is in the defined interval and like wise for tangent.

Originally Posted by johnsy123

I am having a hard time on comprehending where the asymptotes lie on a variety of trig questions.

y= sec(x/2) > [0,2pie]
...

this is pi ...



... and this is pie.