I am getting the wrong answer in this problem
I must find sin, tan, sec, cos, cot, csc
The triangle - 2 on the adjacent and SQRT(3) is on the opposite and i must find the hypotenuse first
Using the theorem A^2+B^2=C^2 i get
(SQRT(3))^2+2^2=C^2
for 3+4=7
But the book says it is SQRT(21)
any suggestions
Thank you

