I am getting the wrong answer in this problem

I must find sin, tan, sec, cos, cot, csc

The triangle - 2 on the adjacent and SQRT(3) is on the opposite and i must find the hypotenuse first

Using the theorem A^2+B^2=C^2 i get

(SQRT(3))^2+2^2=C^2

for 3+4=7

But the book says it is SQRT(21)

any suggestions

Thank you