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Math Help - Solve the following equations for 0<x<360 ?

  1. #1
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    Solve the following equations for 0<x<360 ?

    v) sin^2x=1-cosx
    vi)sin^2x=1
    vii)1-cos^2x=2sin x
    viii) sin^2 x=2cos^2 x
    ix) 2sin^2 x=3cos x
    x) 3tan^2x-10tan x +3=0
    thanks in advance really stuck !
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  2. #2
    MHF Contributor chisigma's Avatar
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    v) \sin^{2} x = 1-\cos x \implies 1-\cos^{2} x = 1-cos x \implies 1+\cos x = 1 \implies \cos x =0...

    Kind regards

    \chi \sigma
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  3. #3
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    Quote Originally Posted by moesizlak View Post
    v) sin^2x=1-cosx

    1 - cos^2x = 1 - cosx

    cosx - cos^2x = 0

    cosx(1 - cosx) = 0

    cosx = 0 , cosx = 1

    x = 90 , 270 ... x = 0 , 360

    same idea with the rest. show us something.
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  4. #4
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    Quote Originally Posted by chisigma View Post
    v) \sin^{2} x = 1-\cos x \implies 1-\cos^{2} x = 1-cos x \implies 1+\cos x = 1 \implies \cos x =0...

    Kind regards

    \chi \sigma
    Though shalt not divide by 0...
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  5. #5
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    Quote Originally Posted by moesizlak View Post
    v) sin^2x=1-cosx
    vi)sin^2x=1
    vii)1-cos^2x=2sin x
    viii) sin^2 x=2cos^2 x
    ix) 2sin^2 x=3cos x
    x) 3tan^2x-10tan x +3=0
    thanks in advance really stuck !
    Please don't post more than two questions in a thread. Otherwise the thread can get convoluted and difficult to follow. See rule #8: http://www.mathhelpforum.com/math-he...ng-151418.html.

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