Can anyone show me how to do this problem?

1+cot^2x-cos^2x-cos^2xcotx^2

This if how far I have gotten

cscx^2-cos^2x-cos^2x (cosx^2/sinx^2)

(1/sinx^2)-cos^2x-cos^2x(cosx^2/sinx^2)

I am not sure how to proceed unfortunately?(Giggle)

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- Jan 23rd 2011, 03:50 PMhomeylova223Basic trigonometric identities problem?
Can anyone show me how to do this problem?

1+cot^2x-cos^2x-cos^2xcotx^2

This if how far I have gotten

cscx^2-cos^2x-cos^2x (cosx^2/sinx^2)

(1/sinx^2)-cos^2x-cos^2x(cosx^2/sinx^2)

I am not sure how to proceed unfortunately?(Giggle) - Jan 23rd 2011, 03:53 PMProve It
What are you trying to show that it is equivalent to?

- Jan 23rd 2011, 04:36 PMhomeylova223
I am supposed to simplify it as much as possible.

- Jan 23rd 2011, 04:57 PMProve It
Get everything to have a common denominator of $\displaystyle \displaystyle \sin^2{x}$ and simplify the numerator...

- Jan 23rd 2011, 04:57 PMskeeter
- Jan 24th 2011, 04:29 PMhomeylova223
I have another trigonometric identities I need some help in although I do not want to start a new thread. It is similar.

cos^4x+2cos^2xsin^2x+sin^4x I need to simplify it this is what I have done thus far

Factor cos^2x

cos^2x+2sin^2x+sin^4x factor out sin^2x

then I get this cos^2x+2+sin^2x But I do not think this is right? - Jan 24th 2011, 04:47 PMskeeter
- Jan 24th 2011, 05:46 PMhomeylova223
Oh it is one.