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Math Help - Simple graphing problem giving me trouble

  1. #1
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    Simple graphing problem giving me trouble

    Hi all. Simple problem here, but I'm having a hard time for some reason. It's a graphing problem. The equation is y = sqrt(3) - 2 sin(x). The graph is drawn but different points along the graph need to be named. There are 6 different points needed. They are (0,A) (B,0) (Pi/2,C) (D,0) (4Pi/3,E) and (3Pi/2,F)

    Let me know if I need to explain better. A is obviously sqrt(3) right? I'm having trouble with the rest of the answers. I would like to know why the answers are what they are, and not just the answers. Thanks for your time.
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  2. #2
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    Hello, kep84!

    The equation is; . y \:= \:\sqrt{3} - 2\sin(x)

    The graph is drawn but different points along the graph need to be named.

    There are 6 different points needed.
    They are: . (0,\,A),\;(B,\,0),\;\left(\frac{\pi}{2},\,C\right)  ,\;(D,\,0),\;\left(\frac{4\pi}{3},\,E\right),\;\le  ft(\frac{3\pi}{2},\,F\right)
    You are right: it is a simple problem.

    We are given: . y \:=\:\sqrt{3} - 2\sin(x)


    Given the point: . (0,\,A)

    What exactly is the problem?
    . . It says: x = 0. .Find y.
    Simple, right? . . . y \:=\:\sqrt{3} - 2\sin(0) \:=\:\sqrt{3} - 0 \:=\:\sqrt{3}
    . . Therefore: . A \,=\,\sqrt{3}


    Given the point: . (B,\,0)
    . . It says: . y \,=\,0. .Find x.
    We have: . 0 \:=\:\sqrt{3}-2\sin(x)\quad\Rightarrow\quad \sin(x) \:=\:\frac{\sqrt{3}}{2}\quad\Rightarrow\quad x \,=\,\frac{\pi}{3}

    Generalized: . B \:=\:\begin{Bmatrix}\frac{\pi}{3} + n\pi \\ \frac{2\pi}{3} + n\pi\end{Bmatrix}


    Get the idea?

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  3. #3
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    Yes. Thanks a bunch. It just clicked a minute ago, but thanks for the quick reply anyways. Cool forum here! Later.
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