# Math Help - Establish the following Identities

1. ## Establish the following Identities

$\frac{\sin[x]}{\tan[x]} +\cos[x]=\sec[x]$
I can get this to be 2 cos x = sec x

I cannot see how to get those equal

2. Originally Posted by IDontunderstand
$\frac{\sin[x]}{\tan[x]} +\cos[x]=\sec[x]$
$\displaystyle\frac{\sin{x}}{\frac{\sin{x}}{\cos{x} }}+\cos{x}=\cos{x}+\cos{x}=2\cos{x}$

I don't know how you are going to get sex{x} out of that though

3. Originally Posted by dwsmith
$\displaystyle\frac{\sin{x}}{\frac{\sin{x}}{\cos{x} }}+\cos{x}=\cos{x}+\cos{x}=2\cos{x}$

I don't know how you are going to get sex{x} out of that though
Thank you. That is what I was thinking. Maybe it is a typo.

4. I agree with dwsmith. If you plug in $x=20^{\circ},$ you get an inequality.