Establish the following Identities

**IDontunderstand** · January 17th 2011, 05:43 PM

$\frac{\sin[x]}{\tan[x]} +\cos[x]=\sec[x]$
I can get this to be 2 cos x = sec x

I cannot see how to get those equal

**dwsmith** · January 17th 2011, 05:49 PM

Originally Posted by IDontunderstand

$\frac{\sin[x]}{\tan[x]} +\cos[x]=\sec[x]$

$\displaystyle\frac{\sin{x}}{\frac{\sin{x}}{\cos{x} }}+\cos{x}=\cos{x}+\cos{x}=2\cos{x}$

I don't know how you are going to get sex{x} out of that though

**IDontunderstand** · January 17th 2011, 06:29 PM

Originally Posted by dwsmith

$\displaystyle\frac{\sin{x}}{\frac{\sin{x}}{\cos{x} }}+\cos{x}=\cos{x}+\cos{x}=2\cos{x}$

I don't know how you are going to get sex{x} out of that though

Thank you. That is what I was thinking. Maybe it is a typo.