hi, i need to find the missing angle from this shape: im not really sure how to do this so if someone could tell me i will be very grateful!
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Have you covered the cosine rule? which may also be written as Edit: Misread angle as a side - use the law of sines instead (post left here for continuity)
Last edited by e^(i*pi); Jan 17th 2011 at 08:52 AM.
would c^2= 6, a^2= 10 and b^2= 96??
Law of sines ... solve for
Originally Posted by andyboy179 would c^2= 6, a^2= 10 and b^2= 96?? My apologies, I misread that angle as a side. Instead you can use the sine rule In this case you have
Last edited by e^(i*pi); Jan 17th 2011 at 10:45 AM. Reason: latex
would i start it like this?
Yes, that's fine. Me and skeeter used the other way of writing it which is the same as you but flipped over. I have started it off in post 6
would i then do sin?= 6x10/sin96=60.33?
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