Can anyone help me find the phase shift for this equation

y=-4 cos(pi/6)(1)+c)+77

According to the back of my book the phase shift is .5 but I am not sure how to find that can anyone help me?(Bow)

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- Jan 16th 2011, 04:22 PMhomeylova223Finding the phase shift?
Can anyone help me find the phase shift for this equation

y=-4 cos(pi/6)(1)+c)+77

According to the back of my book the phase shift is .5 but I am not sure how to find that can anyone help me?(Bow) - Jan 16th 2011, 04:32 PMdwsmith
- Jan 16th 2011, 04:41 PMpickslides
I think the OP requires the horizontal shift which is 'c' in $\displaystyle \displastyle y=A\cos b(x-c)+d$

Can the OP please re-post the equation as the brackets are not complete. - Jan 16th 2011, 04:48 PMhomeylova223
They do not give me C they want me to find it. However I cannot find it this is what I have done

y=-4 cos (pi/6(1)-c)+77

-77=-4cos(pi/6-c)

19.5=cos(pi/6-c)

And this is where I am stuck really the problem claim it is a sinusoidal function if that help explain things.

But they gave me the amplitude, the vertical shift, and the period but they did not give me c or the phase shift so I guess they want me to find it inside the function. - Jan 16th 2011, 04:53 PMhomeylova223
Sorry I mean c=.5 I just dont know how to find c. So I am trying to use the equation to find c.