I have a question about work done by force:

If a 10N (newton) force acting in the direction of vector (1,1) moves an object from P =(-2,1) to Q=(5,6) calculate the work done. Distance measured in metres.

I did vector PQ

Q-P = (5,6) - (-2,1) = (7,5)

Absolute value PQ = sqrt7^2 + 5^2 = sqrt74

vector (1,1) is a 45 degree angle or 1/sqrt2

next, work = (force)(QP)(1/sqrt2)

10sqrt74(1/sqrt2)

Im getting 5sqrt148 but the correct answer is 60sqrt2