Can somebody show me how to finish this one off? I know that the answer is $\displaystyle [0, \frac{\pi}{4})$ and $\displaystyle (\frac{5\pi}{4},2\pi]$, but I don't know how to lay this out. Here is what I have:

$\displaystyle \sin{x} > \cos{x}$

$\displaystyle \sin{x} - \sin{(\frac{\pi}{2}-x}) > 0$

Not sure how to solve this algebraically.

Thanks.