Calculating new Lat/Long from current point, distance & bearing

I have been hitting myself over the head for a couple hours now. I am trying to calculate the new latitude & longitude (position) when all I have is old latitude & longitude, distance traveled and direction.

The formula I found online is:

'lat2 = asin(sin(lat1)*cos(d/R) + cos(lat1)*sin(d/R)*cos(θ))

'lon2 = lon1 + atan2(sin(θ)*sin(d/R)*cos(lat1), cos(d/R)−sin(lat1)*sin(lat2))

'd/R is the angular distance (in radians), where d is the distance travelled and R is the earth’s radius

Any ideas where I may be going wrong? I am getting really strange numbers for output. My Longitude appears fine, but Latitude gives me a number of 0.11xxxxx. I am actually trying to make a litte console application in Visual Basic.net (if anyone here does a little programming, so I included the source code as well)

Sub Main()

Dim latA, lonA As Double

Dim d, θ As Integer

Dim R As Integer = 6372.795477598 ' km

Console.Write("enter latitude: ")

latA = Console.ReadLine

Console.Write("enter longitude: ")

lonA = Console.ReadLine

Console.Write("distance: (meters) ")

d = Console.ReadLine 'distance in meters

Console.Write("vector/course: ")

θ = Console.Read 'bearing in degrees

d = (d / R) ' convert distance to radians

Dim latB, lonB As Double

latB = Asin(Sin(latA) * Cos(d / R) + Cos(latA) * Sin(d / R) * Cos(θ))

lonB = lonA + Atan2(Sin(θ) * Sin(d / R) * Cos(latA), Cos(d / R) - Sin(latA) * Sin(latB))

Console.WriteLine("destination = " & latB & ", " & lonB)

End Sub