sin(5x-((4π)/3) = 1/2

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- Dec 28th 2010, 01:04 PM #1

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- Dec 28th 2010, 01:08 PM #2

- Dec 28th 2010, 01:08 PM #3
Work backwards from the information given. (Are you sure there isn't a interval to solve over? Something like $\displaystyle 0 \leq x \leq 2\pi$)

$\displaystyle 5x - \dfrac{4\pi}{3} = \arcsin \left(\dfrac{1}{2}\right)$

If you know your special triangles then you will know that $\displaystyle \arcsin \left(\dfrac{1}{2}\right) = \dfrac{\pi}{6} + 2k\pi \ \ ,\ \ k \in \mathbb{Z}$

Then solve the linear equation

edit: that is one epic typo in the title if you meant equation