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Math Help - help with ekvation?

  1. #1
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    help with ekvation?

    sin(5x-((4π)/3) = 1/2
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  2. #2
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    pickslides's Avatar
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    Quote Originally Posted by paulaa View Post
    sin(5x-((4π)/3) = 1/2
    Hi there, I assume you need to solve for x ?

    recall \sin \frac{\pi}{6} = \frac{1}{2}

    Can you continue?
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  3. #3
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    e^(i*pi)'s Avatar
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    Work backwards from the information given. (Are you sure there isn't a interval to solve over? Something like 0 \leq x \leq 2\pi)

    5x - \dfrac{4\pi}{3} = \arcsin \left(\dfrac{1}{2}\right)

    If you know your special triangles then you will know that  \arcsin \left(\dfrac{1}{2}\right) = \dfrac{\pi}{6} + 2k\pi \ \ ,\ \ k \in \mathbb{Z}

    Then solve the linear equation


    edit: that is one epic typo in the title if you meant equation
    Last edited by e^(i*pi); December 28th 2010 at 01:09 PM. Reason: latex
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