and That should do it.
Hi guys I am having real difficulty cracking this tri identity.
square root 2 sin (theta- pi/4) = sin theta - cos theta
I have attempted it ever so slightly but am struggling at transposing the LHS to match the RHS
pi/4 I figured was square root 2/2 as a trigonometric value, I thought that this would have some influenece in cancelling out the initial square root of 2.
Another thought was to calculate the pi/4 = 0.785 and also square root of 2 sin = 1.414.
Again I am not entirely sure which path or direction to take with this one, any help would be massively appreciated.
Thanks in advance
Thanks Coffee machine,
Very kind, please can you explain how you transposed to get to the result that you did, I was confused about how I can get rid of the initial square root of 2 (space) sin?,...... crikey I have been banging my head on this one for over a week.