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Math Help - Help with this???

  1. #1
    nik
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    Help with this???

    Does anyone know:- how to make x the subject of the formula below

    4000=0.433arctan(0.544x/1-0.25x)

    Any assistance would be appreciated.

    Nik
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  2. #2
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    Quote Originally Posted by nik View Post
    Does anyone know:- how to make x the subject of the formula below

    4000=0.433arctan(0.544x/1-0.25x)

    Any assistance would be appreciated.

    Nik
    1)Divide by .433 both sides.
    2)Take the tangent of both sides.
    3)You are left with \frac{.544x}{1-.25x}=N where N is the result after 1&2.
    4)Thus, .544x=N-.25xN
    .544x+.25xN=N
    x(.544+.25N)=N
    x=\frac{N}{.25N+.544}
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  3. #3
    nik
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    Quote Originally Posted by ThePerfectHacker View Post
    1)Divide by .433 both sides.
    2)Take the tangent of both sides.
    3)You are left with \frac{.544x}{1-.25x}=N where N is the result after 1&2.
    4)Thus, .544x=N-.25xN
    .544x+.25xN=N
    x(.544+.25N)=N
    x=\frac{N}{.25N+.544}
    When you say tangent of both sides, confirm the following below?
    tan(4000/.433)=tan[arctan(.544x/1-.25x)]
    where N = 4000/.433
    therefore
    tan n = .544x/1-.25x

    Thanks
    Nik
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  4. #4
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    Yes that is how you do it
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