sinusoidal function

**terminator** · December 16th 2010, 03:00 PM

the amplitude is (max -min)/2 = 13-1/2=6
is b=2pi/period , the period seems to be about 6, so b=pi/3
c = horizontal shift(I doesn't seem to be a horizontal shift). How do I calculate it?

d= (max+min)/2 = 13 + 1/2=14/2=7

**Sudharaka** · December 16th 2010, 04:04 PM

Originally Posted by terminator

the amplitude is (max -min)/2 = 13-1/2=6
is b=2pi/period , the period seems to be about 6, so b=pi/3
c = horizontal shift(I doesn't seem to be a horizontal shift). How do I calculate it?

d= (max+min)/2 = 13 + 1/2=14/2=7

Dear terminator,

According to the details you have found,

$y=6\sin\{\frac{\pi}{3}\left(x+c\right)\}+7$

When $x=0\Rightarrow y=7$

$7=6\sin\{\frac{\pi}{3}\left(c\right)\}+7\Rightarro w \dfrac{\pi c}{3}=n\pi~where~n\in Z$

$c=3n~where~n\in Z$

Hope this will help you.

**SammyS** · December 16th 2010, 08:00 PM

Originally Posted by Sudharaka

Dear terminator,

According to the details you have found,

$y=6\sin\{\frac{\pi}{3}\left(x+c\right)\}+7$

When $x=0\Rightarrow y=7$

$7=6\sin\{\frac{\pi}{3}\left(c\right)\}+7\Rightarro w \dfrac{\pi c}{3}=n\pi~where~n\in Z$

$c=3n~where~n\in Z$

Hope this will help you.

It's also true that $\displaystyle y'>0$ at $\displaystyle x=0$

so, $\displaystyle {{\pi c}\over{3}}\approx 2\pi n$ .

Thus: $\displaystyle c\approx 6 n$ .

Since the simplest case of $\displaystyle c\approx 6 n$ is when $\displaystyle n=0$ , I would choose $\displaystyle c\approx 0\ .$

Also, it looks like the period is closer to 6.2 than it is to 6, (BTW: That's very close to $\displaystyle 2\pi\ .$ ) so I would say that $\displaystyle b\approx {{\pi}\over{3.1}}\ ,$ maybe even $\displaystyle b\approx 1\ .$

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