Logs and Radicals

-1 = log(2+radical(5))
I don't understand how its equal to -1?

Quote:

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Originally Posted by HELPHELPHELP

-1 = log(2+radical(5))
I don't understand how its equal to -1?

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There must be more to this problem than you posted.
Please always post the entire question.
You are quite right is cannot be -1 as written.

What base is the log?

Base 10 doesn't equal -1.

Base e doesn't equal -1.

This the entire question, but someone please explain to me not solve, how does that part of the equation equal -1?

This equals on my calculator.

Now that makes more sense.
If then .

Can you solve that?

how would i find b?

Quote:

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Originally Posted by Plato

Now that makes more sense.
If then .

Can you solve that?

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How would i find b? So in this case b is not 10 right, so that would mean it would come out as -1 in the calculator right?

How would you solve for b?

k

so now do i use log 1/2+radical 5 to solve for f(-2)?

Such as log#(-2+radical5)?
#= 1/2+radical 5

ok i got that, but how do you find the exponent of a radical?