Cone and Hemisphere

**GAdams** · July 8th 2007, 02:56 AM

(a) pi * r * l = 1/2 (4 * pi * r^2)

l = 2r

(b) I can't do

(c) I can't do

Thanks

**janvdl** · July 8th 2007, 03:10 AM

For b)

Use Pyhtagoras.

$h^2 = l^2 + r^2$

$h = \sqrt{l^2 + r^2}$

**Soroban** · July 8th 2007, 08:25 AM

Hello, GAdams!

(b) Find the perpendicular height, $h$ , of the cone in terms of $r$ .

From the diagram in (a), we can use Pythagorus (as janvdl suggested):

. . $h^2 + r^2\:=\:L^2\quad\Rightarrow\quad h \:=\:\sqrt{L^2 - r^2}$

Since $L = 2r$ , we have: . $h \:=\:\sqrt{(2r)^2 - r^2} \:=\:\sqrt{3r^2}\quad\Rightarrow\quad\boxed{h \:=\:\sqrt{3}r}$

(c) Find the ratio of the volumes of the cone and the hemisphere.

The volume of a cone is: . $V \:=\:\frac{1}{3}\pi r^2h \:=\:\frac{1}{3}\pi r^2(\sqrt{3}r) \:=\:\frac{\sqrt{3}}{3}\pi r^3$

The volume of a hemisphere is: . $\frac{1}{2} \times \frac{4}{3}\pi r^3\:=\:\frac{2}{3}\pi r^3$

The ratio is: . $\frac{V_c}{V_h} \;=\;\frac{\frac{\sqrt{3}}{3}\pi r^3}{\frac{2}{3}\pi r^3} \:=\:\boxed{\frac{\sqrt{3}}{2}}$

**GAdams** · July 8th 2007, 08:44 AM

The volume of a cone is confusing me:

I can't see how you got from 1/3 * pi * sq.rt3r to sq.rt3/3 * pi * r^3

**janvdl** · July 8th 2007, 09:15 AM

I tried googling for the formulas in a), but i struggled to find them. So i couldn't prove that formula. I think i struggled to find the hemisphere one.

So if $l = 2r$ then just plug that in like Soroban did.

Thread: Cone and Hemisphere

LinkBack

Thread Tools

Display

Cone and Hemisphere

Similar Math Help Forum Discussions

centroid of a hemisphere

Optimization: Cone inside a larger cone

Sphere/hemisphere

volume of solid hemisphere

Temperature in Hemisphere

Search Tags