Hi, I would just like to confirm i have the correct answer before I move on. sinx + tanx = tanx (cosx + 1) I found both sides equal 2sinx.......
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With identities you should work only on one side and get it to equal the other: From the RHS $\displaystyle \tan(x)\cos(x) + \tan(x) = \sin(x) + \dfrac{\sin(x)}{\cos(x)} = \sin(x) + \tan(x)$
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