Thread: square based pyramid angle

Hi,

so there is a pyramid with a square base. The sides of the square base all measure 2m and the height if the pyramid is 05 metre. what is the length sides of the triangular pieces?

Since I have two measurements, 0.5 and 2 I am thinking I can use a^+b^2=c^2?

You are right! You can use the Pythagoras's theorem!

Keep thinking...

Originally Posted by Chr2010

Hi,

so there is a pyramid with a square base. The sides of the square base all measure 2m and the height if the pyramid is 05 metre. what is the length sides of the triangular pieces?

Since I have two measurements, 0.5 and 2 I am thinking I can use a^2+b^2=c^2?

If you use with 0.5m and 1.0m, you will find the altitude of one of the face triangles.

Form a triangle with the verticies at the top point of the pyramid, the point at the center of the base, and a point at a corner of the base.

Would I have to divide my base 2m by 2? I am picturing a sting that has fallen from the top of the pyramid and it would only reach to the middle of the floor, so would my base be now 1 metre

Originally Posted by Chr2010

Would I have to divide my base 2m by 2? I am picturing a sting that has fallen from the top of the pyramid and it would only reach to the middle of the floor, so would my base be now 1 metre

It depends upon which triangle you're talking about.