How do i solve this equation? sin(2x) = -(sqrt(2))/2 x = ___ ? ------------------ i think i have to use: sin(2x) = 2sinxcosx
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Hello, vecoma! How do i solve this equation? . . From your basic trig values, you should know that: . . the angle whose sine is . .
Originally Posted by vecoma How do i solve this equation? sin(2x) = -(sqrt(2))/2 x = ___ ? ------------------ i think i have to use: sin(2x) = 2sinxcosx Hi vecoma, expresses the sine of a double angle in terms of the single angle. It only introduces complexity to your problem as you now have 2 trigonometric terms instead of 1. Instead where first find A, then x
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