2sintcost + sint - 2cost - 1 = 0
t = ___pi
what's the exact answer(no decimals)?
You can factorise this...
$\displaystyle \displaystyle 2\sin{t}\cos{t} + \sin{t} - 2\cos{t} - 1 = 0$
$\displaystyle \displaystyle \sin{t}(2\cos{t} + 1) - 1(2\cos{t} + 1) = 0$
$\displaystyle \displaystyle (2\cos{t} + 1)(\sin{t} - 1) = 0$
$\displaystyle \displaystyle 2\cos{t} + 1 = 0$ or $\displaystyle \displaystyle \sin{t} - 1 = 0$.
Go from here.