Hello, youngb11!

First, look at the interval: .

We want to be between 0 and 6.28

We have: .

Recall that the inverse sine has annumber of values.infinite

We want the values between 0 and 6.28, remember?

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

It's the "2" insin 2xthat causes the trouble.

But because of the "3" in3x, we must "go around 3 times": .**

. .

And we havethe solution in the interval.all

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

Am I the only one aware of this?

Am I the only one who teaches this?