Not sure if this is where it goes but yeah :P

The question is

(1+tanx)/(1+cotx) = (sinx)/(cosx)

as in

1 + tanx sinx

______ = _____

1 + cotx cosx

Let x be theta

I am stuck on this question (Headbang)

I am thankful for any help

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- Nov 30th 2010, 04:34 PMkiLzeDVerifying & Proving Trig Identities
Not sure if this is where it goes but yeah :P

The question is

(1+tanx)/(1+cotx) = (sinx)/(cosx)

as in

1 + tanx sinx

______ = _____

1 + cotx cosx

Let x be theta

I am stuck on this question (Headbang)

I am thankful for any help - Nov 30th 2010, 04:57 PMharish21
use tanx = 1/cotx :

$\displaystyle \dfrac{1+\tan(x)}{1+\cot(x)}=\dfrac{1+\tan(x)}{1+\ frac{1}{\tan(x)}}$

rest is pretty straightforward.. show your work if you are stuck - Nov 30th 2010, 10:31 PMHallsofIvy
Another way to do this is to change tan and cot into terms of sine and cosine:

$\displaystyle \frac{1+ \frac{sin(x)}{cos(x)}}{1+ \frac{cos(x)}{sin(x)}}$.

Now multiply both numerator and denominator by sin(x)cos(x) to eleminate the "small" fractions.

Then factor and cancel.