The questions asks what is the small angle between clock hands where it shows 11:08
This is not a difficult questions, what I need is the fastest possible solution.
My Solution: We first consider that two hands are on 00:00
I would say an hour is 60 minutes so 360/60 = 6 degree for each minute. Therefore we have 8*6=48 degree for the 08 minutes.
The hour is 11 and is 5*6=30 degree away from 00:00 and we have 30+48=78 degree
BUT, we should also consider that if it's 11:08 then hour hand is moved slightly closer to 00:00 ... but how much? it's that an hour has 60 minutes and (8/60)*6 = 0.8
Therefore the final answer is 78 - 0.8 = 77.2
Is this correct ??? Any faster way???