In Trig Simplification..

**Diesal** · November 28th 2010, 09:09 PM

Does $\frac{sin(x)}{cos(x)} \div cos(x) = \frac{sin(x)}{cos^2(x)}$

**TheCoffeeMachine** · November 28th 2010, 09:20 PM

Of course... why the doubt?

**harish21** · November 28th 2010, 09:20 PM

yes. $\mbox{Since\;\;} \dfrac{\frac{a}{b}}{\frac{c}{d}}= \dfrac{a}{b}\times\dfrac{d}{c}$

you have:

$\dfrac{\frac{\sin(x)}{\cos(x)}}{\frac{\cos(x)}{1}} = \dfrac{\sin(x)}{\cos(x)}\;\dfrac{1}{\cos(x)}=\dfra c{\sin(x)}{\cos^2(x)}$

**Diesal** · November 28th 2010, 09:24 PM

Thanks harish.. I'm terrible at this stuff. I am brilliant with numbers, but I don't understand this trigonometry stuff. I've been thrown into advanced math in grade 11 after making a 94 in math 10.. Now I'm near failure because I have a hard time understanding all the processes in this stuff.

**harish21** · November 28th 2010, 09:28 PM

Do not worry too much. You are on the right track. Keep practicing a lot, and you will be fine!

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