how to draw sin(1/x)? thanks.
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Note that the period is 1/360.(correct me if im wrong) As it seems to me,it would squeeze towards the origin.
Originally Posted by arccos Note that the period is 1/360.(correct me if im wrong) As it seems to me,it would squeeze towards the origin. It does squeeze at the origin, given that I cheated and used software
Originally Posted by e^(i*pi) It does squeeze at the origin, given that I cheated and used software um... how would you approach to this question if there isn't any calculators or computer package. thanks
Ah that's interesting. I'm curious to know why it started to open up. My guess is that when x = 1 it will start to widen. As with eg. sin(x/2) = 720 degree period.
Originally Posted by BabyMilo um... how would you approach to this question if there isn't any calculators or computer package. thanks Start with Then if shows that the graph crosses the x-axis at an "infinite" number of times approaching x=0. The function is non-periodic and approaches 0 as x approaches
Last edited by Archie Meade; November 28th 2010 at 07:14 AM.
Originally Posted by Archie Meade Start with Then if shows that the graph crosses the x-axis at an "infinite" number of times approaching x=0. The function is non-periodic and approaches 0 as x approaches thanks...hope i remember this in my interview :P. but how do you explain the smoothen out as x increase as shown above the graph?
Originally Posted by BabyMilo thanks...hope i remember this in my interview :P. but how do you explain the smoothen out as x increase as shown above the graph? For x has to be a fraction <1, for n to be 1 or >1. n is a natural number. Hence if x is >1, the next time the graph goes towards zero after is when x goes towards infinity.
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