I've been staring at this question...for so long. if cos/theta = 1/3 , find the value of 6sin^2/theta - 6
Last edited by mr fantastic; Nov 26th 2010 at 09:14 PM. Reason: Re-titled.
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Use the Pythagorean Identity: $\displaystyle \displaystyle \sin^2{\theta} + \cos^2{\theta} = 1$. Substitute $\displaystyle \displaystyle \cos{\theta}$ and then rearrange.
Thanks for the tip!!
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