I've been staring at this question...for so long.
if cos/theta = 1/3 , find the value of 6sin^2/theta - 6
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I've been staring at this question...for so long.
if cos/theta = 1/3 , find the value of 6sin^2/theta - 6
Use the Pythagorean Identity:
.
Substituteand then rearrange.
Thanks for the tip!! :D