Anyone have any idea how to solve it? Sqrt of both sides? But it's not a memory value angle... :\

cos^2(x) = 1/2

Results 1 to 7 of 7

- Nov 22nd 2010, 08:37 PM #1

- Joined
- Nov 2010
- Posts
- 2

- Nov 22nd 2010, 08:40 PM #2

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 9

- Nov 22nd 2010, 08:49 PM #3

- Nov 22nd 2010, 11:59 PM #4

- Nov 24th 2010, 11:16 AM #5

- Nov 24th 2010, 10:23 PM #6

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 9

- Nov 25th 2010, 02:37 AM #7

- Joined
- Apr 2005
- Posts
- 18,610
- Thanks
- 2606