Anyone have any idea how to solve it? Sqrt of both sides? But it's not a memory value angle... :\

cos^2(x) = 1/2

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- Nov 22nd 2010, 08:37 PMmathnoob2cos^2(x) = 1/2 ... [o,2π)
Anyone have any idea how to solve it? Sqrt of both sides? But it's not a memory value angle... :\

cos^2(x) = 1/2 - Nov 22nd 2010, 08:40 PMdwsmith
- Nov 22nd 2010, 08:49 PMpickslides
- Nov 22nd 2010, 11:59 PMmr fantastic
- Nov 24th 2010, 11:16 AMdhiab
- Nov 24th 2010, 10:23 PMdwsmith

Therefore, the angles that incorporate the negative values satisfy the equation. - Nov 25th 2010, 02:37 AMHallsofIvy