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Math Help - r formula visualization

  1. #16
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    Quote Originally Posted by arccos View Post
    Well I already looked at the answer so i would pick 1-sqrt(5)(-1).So the point here is to notice that only by equating it to -1 can we obtain all positive values in the maximum value?
    and if so, for the expression to be maximum, there must only be positive values?
    I don't understand what you just said. The expression is maximum when the sine is minimum.
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  2. #17
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  3. #18
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    Quote Originally Posted by arccos View Post
    Of course, you can plot the graph and take its maximum value from it but it really isn't necessary.

    1 - sqrt(5)sin (x+26.57)

    What we can do now is to decide for sin (x+26.57) to be maximum or minimum and that's by equating it to 1 and -1 because the maximum or minimum depends on sin (x+26.57). There is nothing else we can alter in the expression other than that.
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  4. #19
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    Quote Originally Posted by mathaddict View Post
    Of course, you can plot the graph and take its maximum value from it but it really isn't necessary.

    1 - sqrt(5)sin (x+26.57)

    What we can do now is to decide for sin (x+26.57) to be maximum or minimum and that's by equating it to 1 and -1 because the maximum or minimum depends on sin (x+26.57). There is nothing else we can alter in the expression other than that.
    Sorry for the late reply.I think i kind of get what you were trying to bring across to me. 1-(-1) gives you a bigger value than 1-1 ,am i wrong?

    Also,i've heard about cases with ^2(power) and to find the minimum value we have to equate it to 0 as 0^2 = 0 whilst 1 or (-1)^2 will give you a bigger value than if you were to equate it to 0.
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