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Thread: Trigonometry " The Ambiguous Case".

  1. #1
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    Question Trigonometry " The Ambiguous Case".

    I solved for one triangle already but I don't know how to solve the other triangle. Please help me guys..
    So, This is the problem, solve the triangle

    1. A = 35
    a = 5
    b = 8

    So it's gonna be like this right?

    - angle A is Acute
    a < b
    a__bsinA
    5__8sin35
    5>4.59
    therefore two triangles.

    So This is [COLOR="rgb(46, 139, 87)"]my answer for the 1st triangle.[/COLOR]

    B = 66.60
    c = 8.54
    C = 78.4
    CORRECT ME IF I'M WRONG..
    Can anyone teach me how to solve for the other triangle? :|
    Last edited by mr fantastic; Nov 8th 2010 at 10:57 AM. Reason: Title.
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  2. #2
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    Quote Originally Posted by ejaykasai View Post
    I solved for one triangle already but I don't know how to solve the other triangle. Please help me guys..
    So, This is the problem, solve the triangle

    So it's gonna be like this right?

    So This is my answer for the 1st triangle.[/COLOR]

    CORRECT ME IF I'M WRONG..
    Can anyone teach me how to solve for the other triangle? :|
    You have to use the Sine rule (what you obviously did)

    1. From \dfrac{\sin(B)}{\sin(35.8^\circle)}=\dfrac85~\impl  ies~\sin(B)\approx 0.9177....

    2. Since \sin(B) = \sin(180^\circ - B) \implies B\approx 66.6^\circ~\vee~ B \approx 113.4^\circ<br />

    3. You now can calculate the dimensions of the 2nd triangle.
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