# Thread: Trigonometry " The Ambiguous Case".

1. ## Trigonometry " The Ambiguous Case".

So, This is the problem, solve the triangle

1. A = 35°
a = 5
b = 8

So it's gonna be like this right?

- angle A is Acute
a < b
a__bsinA
5__8sin35°
5>4.59
therefore two triangles.

So This is [COLOR="rgb(46, 139, 87)"]my answer for the 1st triangle.[/COLOR]

B = 66.60°
c = 8.54
C = 78.4°
CORRECT ME IF I'M WRONG..
Can anyone teach me how to solve for the other triangle? :|

2. Originally Posted by ejaykasai
So, This is the problem, solve the triangle

So it's gonna be like this right?

So This is my answer for the 1st triangle.[/COLOR]

CORRECT ME IF I'M WRONG..
Can anyone teach me how to solve for the other triangle? :|
You have to use the Sine rule (what you obviously did)

1. From $\dfrac{\sin(B)}{\sin(35.8^\circle)}=\dfrac85~\impl ies~\sin(B)\approx 0.9177...$.

2. Since $\sin(B) = \sin(180^\circ - B) \implies B\approx 66.6^\circ~\vee~ B \approx 113.4^\circ
$

3. You now can calculate the dimensions of the 2nd triangle.