How would you solve this??? $\displaystyle 3sin(6x)cosec(2x)=4$ thanks!
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$\displaystyle 3\sin(6x)\cosec(2x)=4$ $\displaystyle \frac{3\sin(6x)}{\sin(2x)}=4$ Do you know the doblue angle formula for sin?
2sin(x)cos(x) still dont understand.
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